OFFSET
1,1
COMMENTS
For n>=2, a unit square covers the most circumference when it has two diagonally opposite corners on the circumference, forming a chord of length sqrt(2).
A simple upper bound a(n) <= u(n) = ceiling(2*Pi*n/sqrt(2)) would be by sqrt(2) arcs instead of chords, and which is bigger at for instance a(70) = 311 < u(70) = 312 (see A376207).
FORMULA
a(n) = ceiling(Pi/arcsin(sqrt(2)/(2*n))).
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Maurice Clerc, Sep 08 2024
STATUS
approved