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A376066
Minimum number of unit squares needed to cover the circumference of a circle of radius n.
1
4, 9, 14, 18, 23, 27, 32, 36, 40, 45, 49, 54, 58, 63, 67, 72, 76, 80, 85, 89, 94, 98, 103, 107, 112, 116, 120, 125, 129, 134, 138, 143, 147, 152, 156, 160, 165, 169, 174, 178, 183, 187, 192, 196, 200, 205, 209, 214, 218, 223, 227, 232, 236, 240, 245, 249, 254, 258, 263, 267, 272, 276, 280, 285, 289, 294, 298, 303, 307, 311
OFFSET
1,1
COMMENTS
For n>=2, a unit square covers the most circumference when it has two diagonally opposite corners on the circumference, forming a chord of length sqrt(2).
A simple upper bound a(n) <= u(n) = ceiling(2*Pi*n/sqrt(2)) would be by sqrt(2) arcs instead of chords, and which is bigger at for instance a(70) = 311 < u(70) = 312 (see A376207).
FORMULA
a(n) = ceiling(Pi/arcsin(sqrt(2)/(2*n))).
CROSSREFS
Cf. A376207.
Sequence in context: A313042 A313043 A313044 * A313045 A313046 A313047
KEYWORD
easy,nonn
AUTHOR
Maurice Clerc, Sep 08 2024
STATUS
approved