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Lexicographically earliest sequence of positive integers such that for any n > 0, Sum_{k = 1..n} 1/(a(k)*a(n+1-k)) <= 1.
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%I #8 Aug 31 2024 08:32:33

%S 1,2,3,3,4,4,5,5,5,5,6,6,6,7,7,7,7,7,8,8,8,8,8,8,9,9,9,9,9,10,10,10,

%T 10,10,10,11,10,11,11,11,11,11,12,12,12,12,12,12,12,12,13,12,13,13,13,

%U 13,13,13,14,14,14,14,14,14,14,14,14,15,14,15,15,15

%N Lexicographically earliest sequence of positive integers such that for any n > 0, Sum_{k = 1..n} 1/(a(k)*a(n+1-k)) <= 1.

%C The variant with strict inequality (A375814) is finite; is this sequence infinite?

%H Rémy Sigrist, <a href="/A375815/b375815.txt">Table of n, a(n) for n = 1..10000</a>

%e The first terms, alongside the corresponding sums, are:

%e n a(n) Sum {k=1..n} 1/(a(k)*a(n+1-k))

%e -- ---- ------------------------------

%e 1 1 1

%e 2 2 1

%e 3 3 11/12

%e 4 3 1

%e 5 4 17/18

%e 6 4 35/36

%e 7 5 167/180

%e 8 5 14/15

%e 9 5 77/80

%e 10 5 119/120

%e 11 6 77/80

%e 12 6 29/30

%e 13 6 443/450

%e 14 7 3007/3150

%e 15 7 6011/6300

%o (PARI) { for (n = 1, #a = vector(72), if (n==1, a[n] = 1, x = sum(k = 2, n-1, 1/(a[k]*a[n+1-k])); if (x >= 1, break, a[n] = ceil(2/(a[1]*(1-x))););); print1 (a[n]", ");); }

%Y Cf. A375814, A375834.

%K nonn

%O 1,2

%A _Rémy Sigrist_, Aug 30 2024