OFFSET
1,1
COMMENTS
Primes p in A022009 belong to 11 (mod 210), therefore a(n) is congruent to the product of residues {11, 13, 17, 19, 23, 29, 31} (mod 210), hence a(n) is congruent to 193 (mod 210).
Gaps between prime factors are {2, 4, 2, 4, 6, 2}.
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..10000
MATHEMATICA
Map[Times @@ NextPrime[#, Range[0, 6]] &, Select[Prime@ Range[2^20], AllTrue[# + {2, 6, 8, 12, 18, 20}, PrimeQ] &]]
CROSSREFS
KEYWORD
nonn
AUTHOR
Michael De Vlieger, Aug 23 2024
STATUS
approved