OFFSET
4,1
COMMENTS
It is not possible to place 3 independent queens on a 1 X 1 or 2 X 2 or 3 X 3 board.
There is a related sequence of 'uncovered' squares i.e., n^2 - a(n).
There is another sequence denoting the potency of the new queen a(n) - A374933(n).
LINKS
Andrew Howroyd, Table of n, a(n) for n = 4..1000
Index entries for linear recurrences with constant coefficients, signature (1,1,-1).
FORMULA
a(n) = 12*n - 43 - (n mod 2) for n >= 10.
G.f.: x^4*(16 + 9*x - 6*x^2 + x^3 + x^5 + x^6 + 2*x^8)/((1 - x)^2*(1 + x)). - Andrew Howroyd, Nov 13 2025
EXAMPLE
4 X 4 complete coverage with 3 queens
x x x x
x Q x x
x x x Q
Q x x x
5 X 5 complete coverage with 3 queens
Q x x x x
x x x x x
x x x Q x
x x x x x
x x Q x x
6 X 6 incomplete 1 o/s
x x x x o x
Q x x x x x
x x x x x Q
x x x x x x
x x Q x x x
x x x x x x
6 X 6 coverage complete but NOT independent
Q x x x x x
x x x x x x
x x x x q x
x x x x x x
x x q x x x
x x x x x x
7 X 7 best leaves 4 o/s (same layout as 6 X 6 with extra row and column)
There are alternative layouts - how many is not identified.
x x x x o x x
Q x x x x x x
x x x x x Q x
x x x x x x x
x x Q x x x x
x x x x x x o
x x x o x x o
MATHEMATICA
LinearRecurrence[{1, 1, -1}, {16, 25, 35, 45, 55, 66, 77, 88, 101}, 60] (* Paolo Xausa, Jan 18 2026 *)
PROG
(PARI) a(n) = 12*n - 43 - (n % 2) + if(n<10, [11, 9, 6, 5, 2, 2][n-3]) \\ Andrew Howroyd, Nov 13 2025
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
John King, Jul 30 2024
EXTENSIONS
a(6)-a(8) corrected by John King, Sep 17 2024
a(9) corrected using data from Mia Muessig by Andrew Howroyd, Oct 05 2024
STATUS
approved
