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%I #4 Aug 04 2024 20:47:21
%S 1,6,36,252,2016,20160,262080,4717440,122653440,4783484160,
%T 287009049600,26978850662400,4019848748697600,956724002190028800,
%U 365468568836591001600,224763169834503465984000,222965064475827438256128000,357190033290275556086317056000
%N a(n) = (1/5)*Product_{k=0..n} F(k)+5, where F=A000045 (Fibonacci numbers).
%C Trivially, a(n+1)/a(n) is an integer for n>=0, so (a(n)) is a divisibility sequence.
%t q[n_] := Fibonacci[n]
%t p[n_] := Product[q[k] + 5, {k, 0, n}]
%t Table[(1/5)*Simplify[p[n]], {n, 0, 20}]
%Y Cf. A000045.
%K nonn
%O 0,2
%A _Clark Kimberling_, Aug 04 2024
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