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a(n) = n! / (floor(n/3))! - n! / (floor(n/2))!.
0

%I #8 Jul 28 2024 17:05:08

%S 0,0,0,0,12,60,240,1680,18480,45360,574560,6320160,19293120,250810560,

%T 3615131520,10637827200,173837664000,2955240288000,8874542476800,

%U 168616307059200,3378360124339200,10123012406707200,222987858828134400,5128720753047091200

%N a(n) = n! / (floor(n/3))! - n! / (floor(n/2))!.

%F a(n) = A355988(n) - A081125(n). - _Vaclav Kotesovec_, Jul 27 2024

%t Table[n!/(Floor[n/3]!) - n!/(Floor[n/2]!), {n, 0, 24}]

%Y Cf. A000142, A081125, A355988.

%K nonn

%O 0,5

%A _Clark Kimberling_, Jul 25 2024