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%I #9 Jul 06 2024 23:04:36
%S 2,1,1,4,77733,2,1,1,1,3,13,1,9715,1,3,2,1,7,1,4,52999,1,41,2,5,1,
%T 10019,1,1,339,5,5,52,9,20,28,2,10,2,1,27,4,1,2,8,1,1,77,1,5,9,1,10,1,
%U 5,1,1,1,4,2,4,11,1,1,1,3,2,2,4,1,15,2,26,8,1,1,1,1,46,2
%N Simple continued fraction of the 5th root of 109.
%H Greg Martin and Winnie Miao, <a href="https://arxiv.org/abs/1409.2974">abc triples</a>, arXiv:1409.2974 [math.NT], 2014. See p. 5.
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>.
%e 109^(1/5) = 2 + 1/(1 + 1/(1 + 1/(4 + 1/(77733 + ... )))).
%t ContinuedFraction[109^(1/5),80]
%Y Cf. A374357 (decimal expansion), A374359 (decimal expansion of the third convergent).
%K nonn,cofr
%O 0,1
%A _Stefano Spezia_, Jul 06 2024