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A373354
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Triangle read by rows: T(n, k) = [n - k + 1 | k] where [n | k] is defined below.
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0
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1, 1, 1, 1, 1, 1, 1, 2, 3, 1, 1, 2, 1, 3, 1, 1, 2, 2, 3, 3, 1, 1, 2, 0, 1, 0, 3, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 3, 1, 2, 3, 3, 1, 1, 2, 0, 3, 2, 3, 2, 0, 3, 1, 1, 2, 2, 1, 0, 1, 0, 1, 3, 3, 1, 1, 2, 2, 1, 0, 2, 3, 0, 1, 3, 3, 1, 1, 2, 3, 3, 2, 0, 1, 0, 3, 2, 2, 3, 1
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OFFSET
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1,8
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LINKS
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FORMULA
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Let two positive numbers n, k be given. We write (n R k) if two integers x and y exist, such that x^2 = n + k*y, and (n N k) otherwise. If the condition is satisfied n is called a quadratic residue modulo k. We distinguish four cases:
[n | k] := 0 if (n N k) and (k N n);
[n | k] := 1 if (n R k) and (k R n);
[n | k] := 2 if (n R k) and (k N n);
[n | k] := 3 if (n N k) and (k R n).
We set T(n, k) = [n - k + 1 | k].
Exchanging 2 <-> 3 reverses the rows.
All terms of row n are 1 <==> n = 1, 2 or n is of the form k*(k-2), k >= 3.
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EXAMPLE
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Triangle starts:
[ 1] 1;
[ 2] 1, 1;
[ 3] 1, 1, 1;
[ 4] 1, 2, 3, 1;
[ 5] 1, 2, 1, 3, 1;
[ 6] 1, 2, 2, 3, 3, 1;
[ 7] 1, 2, 0, 1, 0, 3, 1;
[ 8] 1, 1, 1, 1, 1, 1, 1, 1;
[ 9] 1, 2, 2, 3, 1, 2, 3, 3, 1;
[10] 1, 2, 0, 3, 2, 3, 2, 0, 3, 1;
[11] 1, 2, 2, 1, 0, 1, 0, 1, 3, 3, 1;
[12] 1, 2, 2, 1, 0, 2, 3, 0, 1, 3, 3, 1;
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MAPLE
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QRS := proc(n, k) local QR, p, q, a, b;
QR := (a, n) -> NumberTheory:-QuadraticResidue(a, n);
a := QR(n, k); b := QR(k, n);
if a = -1 and b = -1 then return 0 fi;
if a = 1 and b = 1 then return 1 fi;
if a = 1 and b = -1 then return 2 fi;
if a = -1 and b = 1 then return 3 fi;
end: for n from 1 to 12 do lprint([n], seq(QRS(n-k+1, k), k = 1..n)) od;
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PROG
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(Python)
from sympy.ntheory import is_quad_residue
def QR(n, k): return is_quad_residue(n, k)
def QRS(n, k):
a = QR(n, k); b = QR(k, n)
if not a and not b: return 0
if a and b: return 1
if a and not b: return 2
if not a and b: return 3
def T(n, k): return QRS(n - k + 1, k)
for n in range(1, 13): print([n], [T(n, k) for k in range(1, n + 1)])
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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