%I #8 May 18 2024 15:24:06
%S 1,0,1,3,6,2,18,63,36,6,189,828,684,216,24,2484,13365,14400,6660,1440,
%T 120,40095,255474,339390,206280,65880,10800,720,766422,5645619,
%U 8915508,6707610,2827440,687960,90720,5040,16936857,141626232,259137144,232306704,121519440,39130560,7680960,846720,40320
%N Triangle read by rows: T(n, k) = (Sum_{i=0..n-k} (-1)^i * binomial(n-k, i) * A007559(n-i)) * n! / ((n-k)! * A007559(k)) for 0 <= k <= n.
%F T(n, k) = (T(n-1, k-1) + 3 * T(n-1, k)) * n for 0 < k < n with initial values T(n, 0) = A033030(n) and T(n, n) = A000142(n).
%F E.g.f. of column k: exp(-t) / (1-3*t)^(1/3) * (t / (1-3*t))^k.
%F E.g.f.: exp(x*t / (1-3*t) - t) / (1-3*t)^(1/3).
%e Triangle T(n, k) starts:
%e n\k : 0 1 2 3 4 5 6 7
%e ======================================================================
%e 0 : 1
%e 1 : 0 1
%e 2 : 3 6 2
%e 3 : 18 63 36 6
%e 4 : 189 828 684 216 24
%e 5 : 2484 13365 14400 6660 1440 120
%e 6 : 40095 255474 339390 206280 65880 10800 720
%e 7 : 766422 5645619 8915508 6707610 2827440 687960 90720 5040
%e etc.
%t T[n_,k_]:=n!SeriesCoefficient[Exp[-t]/ (1-3*t)^(1/3) * (t / (1-3*t))^k,{t,0,n}]; Table[T[n,k],{n,0,8},{k,0,n}]//Flatten (* _Stefano Spezia_, May 18 2024 *)
%o (PARI) T(n, k) = { sum(i=0, n-k, (-1)^i * binomial(n-k, i) * prod(j=1, n-i, 3*j-2)) * n! / ((n-k)! * prod(m=1, k, 3*m-2)) }
%Y Cf. A007559, A033030 (column 0), A000142 (main diagonal).
%K nonn,easy,tabl
%O 0,4
%A _Werner Schulte_, May 16 2024