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%I #13 May 19 2024 12:09:21
%S 2,3,5,7,11,23,13,25,17
%N Let a(1) = 2, f(n) = a(1)*a(2)*...*a(n-1) for n >= 1 and a(n) = nextludicnumber(f(n)+1) - f(n) for n >= 2, where nextludicnumber(x) is the smallest ludic number > x.
%C Conjecture: every element is a ludic number.
%Y Cf. A067836, A003309 (ludic numbers).
%K nonn,more
%O 1,1
%A _Davide Rotondo_, May 07 2024
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