OFFSET
0,2
FORMULA
a(n) = [x^n] 1/((1-x+x^2) * (1-x)^(4*n)).
It appears that a(n) = Sum_{k = 0..n} binomial(3*n+2*k-1, k). - Peter Bala, Jun 04 2024
PROG
(PARI) a(n) = sum(k=0, n\2, (-1)^k*binomial(5*n-k, n-2*k));
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Seiichi Manyama, Apr 06 2024
STATUS
approved