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Expansion of (1/x) * Series_Reversion( x * (1-5*x)^2 / (1-4*x) ).
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%I #12 Mar 20 2024 09:39:36

%S 1,6,71,1046,17231,303876,5611556,107128046,2097177071,41870595806,

%T 849284396751,17451906690856,362539208779396,7601087206512096,

%U 160635649725455256,3418231465333316126,73178876192536066031,1575035438677302619746

%N Expansion of (1/x) * Series_Reversion( x * (1-5*x)^2 / (1-4*x) ).

%H <a href="/index/Res#revert">Index entries for reversions of series</a>

%F a(n) = (1/(n+1)) * Sum_{k=0..n} 4^(n-k) * binomial(2*n+k+1,k) * binomial(2*n,n-k).

%o (PARI) my(N=20, x='x+O('x^N)); Vec(serreverse(x*(1-5*x)^2/(1-4*x))/x)

%o (PARI) a(n) = sum(k=0, n, 4^(n-k)*binomial(2*n+k+1, k)*binomial(2*n, n-k))/(n+1);

%Y Cf. A078009.

%K nonn

%O 0,2

%A _Seiichi Manyama_, Mar 19 2024