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%I #9 Mar 09 2024 11:20:59
%S 2,5,7,8,11,15,17,19,21,23,25,26,35,44,47,50,51,52,53,59,61,65,68,69,
%T 70,71,73,75,76,77,79,80,98,104,106,107,116,128,132,134,140,142,143,
%U 146,150,152,154,155,156,158,159,160,161,176,178,179,184,185,187
%N Numbers m such that c(0) <= c(1) <= c(2), where c(k) = number of k's in the ternary representation of m.
%e The ternary representation of 15 is 120, for which c(0)=1 <= c(1)=1 < c(2)=1. So 15 is in the sequence.
%t Select[Range[1000], DigitCount[#, 3, 0] <= DigitCount[#, 3, 1] <= DigitCount[#, 3, 2] &]
%Y Cf. A007089, A370853, A370854, A370855.
%K nonn,base
%O 1,1
%A _Clark Kimberling_, Mar 03 2024