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%I #7 Mar 02 2024 00:02:45
%S 1,91,-9828,1535868,-294731892,62322050700,-13990450587012,
%T 3270320252339868,-787131217405990548,193694053976566000812,
%U -48497295306135216560292,12313491783703337923916220,-3162498663877264843739477172
%N Expansion of ( (1 + x)*(1 - 17*x)*(1 + 289*x) )^(1/3).
%C The cube root of F(x) = (1 + x)*(1 - (3*k+2)*x)*(1 + (3*k+2)^2*x) is an integer series because F(x) == (1+x)*(1 + 2*x - 8*x^2) == (1+x)^3 (mod 9).
%o (PARI) my(N=20, x='x+O('x^N)); Vec(((1+x)*(1-17*x)*(1+289*x))^(1/3))
%Y Cf. A370145, A370149, A370779.
%K sign
%O 0,2
%A _Seiichi Manyama_, Mar 01 2024