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%I #9 Jan 20 2024 09:34:40
%S 1,5040,403291461126605635584000000,
%T 1982608315404440064116146708361898137544773690227268628106279599612729753600000000000000
%N a(n) = (n^3-1)!.
%F a(n) = (2*Pi)^(1/2 - n^2/2)*(n^2)^(n^3 - 1/2)*Product_{j=0..n^2-1} Gamma(n + j/n^2).
%F a(n) = A000142(A068601(n)).
%p seq((n^3-1)! , n = 1..4);
%Y Cf. A000142, A068601, A256511.
%K nonn
%O 1,2
%A _Karol A. Penson_, Jan 15 2024
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