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Value of A121805(k) for k = A367358(n).
1

%I #12 Nov 22 2023 23:56:19

%S 1,12,35,94,135,248,331,461,530,651,744,809,908,1068,2070,3039,4093,

%T 5012,6013,7042,8026,9055,10058,20047,30092,40017,50008,60054,70063,

%U 80065,90022,100058,200051,300060,400093,500028,600074,700013,800022,900055,1000006,2000047,3000008,4000061,5000034,6000055,7000008,8000056,9000013,10000036,20000038,30000029,40000039,50000030,60000051,70000064,80000064,90000077

%N Value of A121805(k) for k = A367358(n).

%C These are the terms in A121805 where either the leading digit or the length has just changed.

%o (Python)

%o def agen(): # generator of terms

%o n, an, y, prev_lead, prev_length = 1, 1, 1, None, None

%o while y < 10:

%o san = str(an)

%o lead, length = san[0], len(san)

%o if lead != prev_lead or length != prev_length:

%o yield an

%o an, y = an + 10*(an%10), 1

%o while y < 10:

%o if str(an+y)[0] == str(y):

%o an += y

%o break

%o y += 1

%o n, prev_lead, prev_length = n+1, lead, length

%o print(list(agen())) # _Michael S. Branicky_, Nov 22 2023

%Y Cf. A121805, A366487, A367358.

%K nonn,base,fini,full

%O 1,2

%A _N. J. A. Sloane_, Nov 21 2023

%E More than the usual number of terms are shown in order to match the data in A367358.

%E More terms from _Michael S. Branicky_, Nov 22 2023