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%I #11 Feb 25 2024 02:16:48
%S 0,0,1,1,1,2,1,2,2,2,1,4,1,2,3,3,1,4,1,4,3,3,1,6,3,2,3,5,2,6,1,4,4,2,
%T 4,8,2,2,3,6,2,6,1,6,5,3,2,9,2,6,5,6,2,6,4,7,4,5,3,11,1,2,5,6,5,8,2,6,
%U 4,8,2,12,2,4,6,6,5,7,1,8,6,4,5,12,3,4
%N Number of distinct prime divisors of A001045(n) (Jacobsthal numbers).
%H Amiram Eldar, <a href="/A366769/b366769.txt">Table of n, a(n) for n = 1..1122</a>
%F a(n) = omega(Jacobsthal(n)) = A001221(A001045(n)).
%e a(12) = 4 because Jacobsthal(12) = 1365 has prime factors {3, 5, 7, 13}.
%Y Cf. A001045, A001221, A022307, A086598, A364818, A366770.
%K nonn
%O 1,6
%A _Sean A. Irvine_, Oct 21 2023
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