%I #11 Oct 13 2023 11:46:17
%S 4373612677928697257861252602371390152816537558161613618621437993378423467772036,
%T 36875131794129999827197811565225474825492979968971970996283137471637224634055579,
%U 154476802108746166441951315019919837485664325669565431700026634898253202035277999
%N Triples of positive integers (a,b,c) with a<=b<=c such that a/(b+c) + b/(c+a) + c/(a+b) = 4.
%C Solution of a meme/puzzle that has been circulating on the web. The first 3 terms form the smallest solution.
%H Andrew Bremner and Allan Macleod, <a href="http://ami.ektf.hu/uploads/papers/finalpdf/AMI_43_from29to41.pdf">An unusual cubic representation problem</a>, Annales Mathematicae et Informaticae, 43(2014), pp.29-41.
%H Quora, <a href="https://www.quora.com/How-do-you-find-the-positive-integer-solutions-to-frac-x-y+z-+-frac-y-z+x-+-frac-z-x+y-4">How do you find the positive integer solutions to x/(y+z)+y/(z+x)+z/(x+y)=4?</a>
%Y Cf. A283564, A309170, A309168, A309177, A309178.
%K nonn
%O 1,1
%A _Chai Wah Wu_, Oct 12 2023