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%I #18 Nov 18 2023 13:13:12
%S 4,48,129,221,233,265,318,402,426,490,494,539,635,691,708,795,853,891,
%T 910,919,1010,1011,1022,1043,1074,1115,1166,1227,1298,1379,1470,1471,
%U 1482,1503,1534,1575,1626,1687,1758,1839,1930,1931,1942,1963,1994,2036,2098,2180,2182
%N Analog of A121805, but starting with 4.
%C If instead we start with 3, the sequence is the two-term sequence [3, 36].
%C The present sequence is finite, with last term a(199900) = 9999945.
%H N. J. A. Sloane, <a href="/A366492/b366492.txt">Table of n, a(n) for n = 1..20000</a>
%o (Python)
%o from itertools import islice
%o def agen(start=4): # generator of terms
%o an, y = start, 1
%o while y < 10:
%o yield an
%o an, y = an + 10*(an%10), 1
%o while y < 10:
%o if str(an+y)[0] == str(y):
%o an += y
%o break
%o y += 1
%o print(list(islice(agen(), 50))) # _Michael S. Branicky_, Nov 18 2023
%Y Comma sequences in base 10, starting with 1, 2, 4, 5, 6, 7, 8, 9, 10 are A121805, A139284, A366492, A367337, A367350, A367351, A367352, A367353, A367354. Starting with 3 is trivial, and those starting with 11, 12, 13 are essentially duplicates.
%Y Cf. A330128, A330129.
%K nonn,base,fini
%O 1,1
%A _N. J. A. Sloane_, Nov 14 2023
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