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O.g.f. A(x) satisfies: A(x) = 1 + x*Sum_{n>=0} 2^n * log( A(3^n*x) )^n / n!.
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%I #12 Oct 17 2023 09:34:47

%S 1,1,6,261,56070,56526498,334429044030,15777272891508021,

%T 6500948711591606135796,22416650201723925643982814186,

%U 632905244163070372226486183732882316,146120187946706698644410320973489902454862324,277121097159744219425840626808464318501357604841881466

%N O.g.f. A(x) satisfies: A(x) = 1 + x*Sum_{n>=0} 2^n * log( A(3^n*x) )^n / n!.

%C In general, we have the following identity:

%C given A(x) = Sum_{n>=0} a(n)*x^n satisfies

%C A(x) = 1 + x*Sum_{n>=0} p^n * log( A(q^n*x) )^n / n!,

%C then a(n+1) = [x^n] A(x)^(p*q^n) for n >= 0, with a(0)=1,

%C for arbitrary fixed parameters p and q.

%C Here, p = 2 and q = 3.

%H Paul D. Hanna, <a href="/A366226/b366226.txt">Table of n, a(n) for n = 0..50</a>

%F G.f. A(x) = Sum_{n>=0} a(n)*x^n satisfies the following formulas.

%F (1) A(x) = 1 + x*Sum_{n>=0} 2^n*log( A(3^n*x) )^n / n!.

%F (2) a(n+1) = [x^n] A(x)^(2*3^n) for n >= 0, with a(0)=1.

%e G.f.: A(x) = 1 + x + 6*x^2 + 261*x^3 + 56070*x^4 + 56526498*x^5 + 334429044030*x^6 + 15777272891508021*x^7 + 6500948711591606135796*x^8 + ...

%e where

%e A(x) = 1 + x*[1 + 2*log(A(3*x)) + 2^2*log(A(3^2*x))^2/2! + 2^3*log(A(3^2*x))^3/3! + ... + 2^n*log(A(3^n*x))^n/n! + ...].

%e RELATED SERIES.

%e log(A(x)) = x + 11*x^2/2 + 766*x^3/3 + 223187*x^4/4 + 282345766*x^5/5 + 2006233236098*x^6/6 + 110438567161208518*x^7/7 + ...

%e RELATED TABLE.

%e The table of coefficients of x^k in A(x)^(2*3^n) begins:

%e n=0: [1, 2, 13, 534, 112698, 113168268, ...];

%e n=1: [1, 6, 51, 1766, 345165, 340906254, ...];

%e n=2: [1, 18, 261, 7350, 1112382, 1035922644, ...];

%e n=3: [1, 54, 1755, 56070, 4589001, 3250238022, ...];

%e n=4: [1, 162, 14013, 894294, 56526498, 12817431900, ...];

%e n=5: [1, 486, 120771, 20555046, 2731197285, 334429044030, ...]; ...

%e in which the main diagonal equals this sequence shift left,

%e illustrating that a(n+1) = [x^n] A(x)^(2*3^n) for n >= 0.

%o (PARI) {a(n) = my(A=[1, 1]); for(i=1, n, A=concat(A, Vec(Ser(A)^(2*3^(#A-1)))[ #A])); A[n+1]}

%o for(n=0,15,print1(a(n),", "))

%o (PARI) {a(n) = my(A=1+x); for(i=1, n, A = 1 + x*sum(m=0,#A, 2^m*log( subst(Ser(A),x,3^m*x +x*O(x^n)))^m/m!) ); polcoeff(A,n)}

%o for(n=0,15,print1(a(n),", "))

%Y Cf. A132695, A156904, A156905, A181444.

%K nonn

%O 0,3

%A _Paul D. Hanna_, Oct 16 2023