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A363188 Prime numbers that are the exact average of four consecutive odd semiprimes. 8

%I #18 Jul 05 2023 12:18:56

%S 53,67,89,199,223,277,349,439,449,461,487,491,499,523,557,569,643,683,

%T 877,883,929,941,1069,1153,1259,1361,1471,1487,1733,1787,1901,1933,

%U 1951,2111,2129,2251,2297,2311,2371,2521,2557,2689,2777,2797,2861,2917,2939,3037,3041,3253,3259,3271,3407

%N Prime numbers that are the exact average of four consecutive odd semiprimes.

%e 53 is a term because (49 + 51 + 55 + 57)/4 = 53 is prime.

%e 67 is a term because (57 + 65 + 69 + 77)/4 = 67 is prime.

%p OP:= select(isprime,[seq(i,i=3..10000,2)]):

%p OSP:= sort(select(`<=`,[seq(seq(OP[i]*OP[j],j=1..i),i=1..nops(OP))],3*OP[-1])):

%p SA:= [seq(add(OSP[i+j],j=0..3)/4,i=1..nops(OSP)-3)]:

%p select(t -> t::integer and isprime(t), SA); # _Robert Israel_, May 21 2023

%t Select[Plus @@@ Partition[Select[Range[1, 3500, 2], PrimeOmega[#] == 2 &], 4, 1] / 4, PrimeQ] (* _Amiram Eldar_, May 21 2023 *)

%o (Python)

%o from itertools import count, islice

%o from sympy import factorint, isprime

%o def semiprime(n): return sum(e for e in factorint(n).values()) == 2

%o def nextoddsemiprime(n): return next(k for k in count(n+1+(n&1), 2) if semiprime(k))

%o def agen(): # generator of terms

%o osp = [9, 15, 21, 25]

%o while True:

%o q, r = divmod(sum(osp), len(osp))

%o if r == 0 and isprime(q):

%o yield q

%o osp = osp[1:] + [nextoddsemiprime(osp[-1])]

%o print(list(islice(agen(), 53))) # _Michael S. Branicky_, May 21 2023

%Y Cf. A000040, A046315.

%Y Cf. A363074, A363187.

%K nonn

%O 1,1

%A _Elmo R. Oliveira_, May 20 2023

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Last modified June 25 17:15 EDT 2024. Contains 373706 sequences. (Running on oeis4.)