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%I #13 Aug 29 2023 10:12:16
%S 0,0,1,2,4,4,7,10,14,18,23,26,32,38,43,50,58,64,73,80,90,100,111,120,
%T 132,144,157,168,182,192,207,222,238,254,269,284,302,320,339,356,376,
%U 392,413,434,452,474,497,518,542,566,591,616,642,666,693,718,746,774,803,826,856,886,915,946,978
%N a(n) = (A000982(n) - A362931(n))/2.
%C a(n) = one-half of (number of pairs (i,j) in [1..n] X [1..n] with integral arithmetic mean) - (number of pairs (i,j) in [1..n] X [1..n] with integral harmonic mean).
%H Alois P. Heinz, <a href="/A362937/b362937.txt">Table of n, a(n) for n = 1..10000</a>
%o (Python)
%o def A362937(n): return ((n-1)**2>>2)-sum(1 for x in range(1,n+1) for y in range(1,x) if not (x*y<<1)%(x+y)) # _Chai Wah Wu_, Aug 29 2023
%Y Cf. A000982, A362931-A362936.
%K nonn
%O 1,4
%A _N. J. A. Sloane_, Aug 28 2023
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