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a(n) = K(4,n), where K(M,n) = 2*(2*M+3)!*(4*n+2*M+1)!/((M+2)!*M!*n!*(3*n+2*M+3)!).
1

%I #5 Apr 13 2023 00:20:50

%S 42,330,2310,16170,115500,844074,6301680,47948670,370952010,

%T 2911858950,23150207388,186127769100,1511405695800,12382019142570,

%U 102244420000800,850316530400304,7117336900424520,59922942071869800,507204902536897950

%N a(n) = K(4,n), where K(M,n) = 2*(2*M+3)!*(4*n+2*M+1)!/((M+2)!*M!*n!*(3*n+2*M+3)!).

%H K. A. Penson, K. Górska, A. Horzela, and G. H. E. Duchamp, <a href="https://arxiv.org/abs/2209.06574">Hausdorff moment problem for combinatorial numbers of Brown and Tutte: exact solution</a>, arXiv:2209.06574 [math.CO], 2022.

%Y Cf. A000260, A197271, A341853, A341854, A362104.

%K nonn

%O 0,1

%A _N. J. A. Sloane_, Apr 13 2023