%I #14 Mar 23 2023 23:09:03
%S 1,1,1,1,2,1,1,1,2,1,2,1,2,1,1,1,2,1,2,1,2,1,2,1,2,1,2,1,1,1,1,1,2,1,
%T 2,1,2,1,2,1,1,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,1,1,2,1,1,1,1,1,2,1,
%U 1,1,2,1,2,1,2,1,1,1,2,1,2,1,1,1,2,1,2,1
%N a(n) is the denominator of the median of the distinct prime factors of n.
%H Winston de Greef, <a href="/A361631/b361631.txt">Table of n, a(n) for n = 2..10000</a>
%F For p a prime, a(p^k) = 1.
%e a(12) = 2 since the distinct prime factors of 12 are 2 and 3, of median equal to 5/2.
%e a(30) = 1 since the distinct prime factors of 30 are 2, 3, and 5, of median equal to 3.
%t a[n_]:=Denominator[Median[FactorInteger[n][[All, 1]]]]; Array[a,88,2]
%o (PARI) a(n)=my(f=factor(n)[,1]~, i=length(f)); denominator(if(i%2, f[i\2+1], (f[i/2]+f[i/2+1])/2)) \\ _Winston de Greef_, Mar 23 2023
%Y Cf. A001221, A027748, A323172, A361566, A361630 (numerator), A361633 (with multiplicity).
%K nonn,frac
%O 2,5
%A _Stefano Spezia_, Mar 18 2023