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a(n) is the smallest integer k > 3 that satisfies k mod j <= 3 for all integers j in 1..n.
3

%I #36 Jun 20 2023 15:00:51

%S 4,4,4,4,5,6,7,8,56,72,91,651,651,1080,1080,1443,20163,20163,246962,

%T 246962,246962,609843,2162162,2162162,29055601,29055601,107881202,

%U 107881202,205405203,205405203,3625549202,5675443203,8374212002,8374212002,8374212002,8374212002,131668891200,131668891200

%N a(n) is the smallest integer k > 3 that satisfies k mod j <= 3 for all integers j in 1..n.

%H Chai Wah Wu, <a href="/A361248/b361248.txt">Table of n, a(n) for n = 1..48</a>

%F For n > 2, n <= a(n) < A003418(n). - _Charles R Greathouse IV_, Apr 27 2023

%e a(11)=91 since 91 mod 11 = 3, 91 mod 10 = 1, 91 mod 9 = 1, 91 mod 8 = 3, 91 mod 7 = 0, 91 mod 6 = 1, 91 mod 5 = 1, 91 mod 4 = 3, 91 mod 3 = 1, 91 mod 2 = 1, 91 mod 1 = 0 and 91 is the smallest integer greater than 3 where all of these remainders are 3 or less.

%o (Python)

%o final=100

%o k=4

%o for n in range(1, final+1):

%o j = n+1

%o while (j > 3):

%o j -= 1

%o if k%j>3:

%o k += j-(k%j)

%o j = n+1

%o print(k)

%o (PARI) isok(k, n) = for (j=5, n, if ((k % j) > 3, return(0))); return(1);

%o a(n) = my(k=4); while(!isok(k, n), k++); k; \\ _Michel Marcus_, Mar 17 2023

%Y Cf. A003418 (all remainders 0).

%Y Cf. A361246, A361247.

%K nonn

%O 1,1

%A _Andrew Cogliano_, Mar 05 2023