OFFSET
1,2
COMMENTS
Imagine the offset of A361103 is 1, and assume it really is a permutation of the natural numbers. In tabular form, it is
..1..2..3..4..5..6..7..8..9.10.11...
..1..2..3..6.11.14.10..7..5.16..19...
Then the inverse permutation would be
..1..2..3.17..9..4..8.31.15..7..5.47...
which is the present sequence.
LINKS
N. J. A. Sloane, Table of n, a(n) for n = 1..2721
EXAMPLE
A361103(16) = 4, so a(4) = 17.
CROSSREFS
KEYWORD
nonn
AUTHOR
Scott R. Shannon and N. J. A. Sloane, Mar 02 2023
EXTENSIONS
Edited by N. J. A. Sloane, Mar 04 2023
STATUS
approved