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G.f. satisfies A(x) = 1 + x * (1 - x)^2 * A(x * (1 - x)).
0

%I #8 Feb 28 2023 06:48:16

%S 1,1,-1,-3,4,12,-38,-33,428,-696,-3640,23140,-24766,-358024,2254416,

%T -2636188,-48229769,372329934,-777177980,-8375653981,92394060425,

%U -351172999190,-1461026905290,30190430840555,-192411489098224,66898238530023,11177278011895383

%N G.f. satisfies A(x) = 1 + x * (1 - x)^2 * A(x * (1 - x)).

%F a(0) = 1; a(n) = Sum_{k=0..n-1} (-1)^k * binomial(n+1-k,k) * a(n-1-k).

%o (PARI) a_vector(n) = my(v=vector(n+1)); v[1]=1; for(i=1, n, v[i+1]=sum(j=0, i-1, (-1)^j*binomial(i+1-j, j)*v[i-j])); v;

%Y Cf. A360887, A360894.

%K sign

%O 0,4

%A _Seiichi Manyama_, Feb 27 2023