login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A359438 For n >= 0, let S be the sequence of numbers m such that (m^2 - 2*n^2 + 1)/2 is a square. Then a(n) is the number k such that S(j) = 6*S(j-k) - S(j-2k) for all j for which S(j-2k) is defined. 0

%I #6 Jan 01 2023 09:48:32

%S 1,1,2,2,2,3,2,2,2,4,2,2,4,2,4,2,4,2,2,4,4,2,2,4,2,2,4,4,2,3,4,4,4,4,

%T 2,4,2,8,2,2,4,2,2,2,6,2,2,4,4,2,2,4,2,4,8,4,2,4,6,2,4,4,2,2,2,8,4,4,

%U 4,2,4,4,4,2,4,4,2,4,4,4,2,2,8,4,4,2,4

%N For n >= 0, let S be the sequence of numbers m such that (m^2 - 2*n^2 + 1)/2 is a square. Then a(n) is the number k such that S(j) = 6*S(j-k) - S(j-2k) for all j for which S(j-2k) is defined.

%F a(0) = 1; for n >= 1, a(n) = A000005(2*n^2 - 1).

%e For n = 0, {S(j)} = A002315 (the NSW numbers), which satisfies S(j) = 6*S(j-1) - S(j-2), so a(0) = 1.

%e For n = 1, {S(j)} = A001541, which also satisfies S(j) = 6*S(j-1) - S(j-2), so a(1) = 1.

%e For n = 2, {S(j)} = A077443, which satisfies S(j) = 6*S(j-2) - S(j-4), so a(2) = 2.

%e For n = 5, {S(j)} = A106525, which satisfies S(j) = 6*S(j-3) - S(j-6), so a(5) = 3.

%Y Cf. A000005, A002315, A001541, A077443, A077242, A106525.

%K nonn

%O 0,3

%A _Jon E. Schoenfield_, Dec 31 2022

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified August 25 16:19 EDT 2024. Contains 375439 sequences. (Running on oeis4.)