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%I #4 Dec 24 2022 11:12:51
%S 1,2,4,5,8,9,10,16,17,18,19,20,21,32,33,34,35,36,37,38,39,40,41,42,64,
%T 65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,128,
%U 129,130,131,132,133,134,135,136,137,138,139,140,141,142,143
%N Numbers k such that A359194(k) < k.
%C The first run of consecutive values has length 2 and initial value 1.
%C For k > 1, the k-th run of consecutive values has length A005578(k) and initial value 2^k.
%e A359194(42) = 1 < 42, so 42 belongs to this sequence.
%o (PARI) is(n) = if(n, bitneg(3*n, exponent(3*n)+1), 1) < n
%Y Cf. A005578, A359194, A359266 (complement).
%K nonn,base
%O 1,2
%A _Rémy Sigrist_, Dec 23 2022