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A358717 A sequence of sorted primes 2 = p_1 < p_2 < ... < p_m such that (p_i + 1)/2 divides the product p_1*p_2*...*p_(i-1) of the earlier primes and each prime factor of (p_i-1)/2 is a prime factor of the product. 2

%I #18 Feb 19 2024 22:52:54

%S 2,3,5,11,19,37,73,109,1459,2179,2917,4357,8713

%N A sequence of sorted primes 2 = p_1 < p_2 < ... < p_m such that (p_i + 1)/2 divides the product p_1*p_2*...*p_(i-1) of the earlier primes and each prime factor of (p_i-1)/2 is a prime factor of the product.

%C The sequence was used, together with A358718 and A358719, by Ferrari and Sillari (Preprint-2022) to prove that there are at least three solutions n to phi(n+k) = 2* phi(n) for all even k <= 4*10^58.

%C I have checked up to 10^8 and found no more terms.

%C Prime a(14) does not exist, which can be established by going over the divisors d of the product a(1)*...*a(13) and testing 2*d-1 as a candidate for a(14). - _Max Alekseyev_, Feb 19 2024

%H M. Ferrari and L. Sillari, <a href="https://arxiv.org/abs/2110.05401">On the minimal number of solutions of the equation phi(n+k) = M*phi(n), M=1,2</a>, arXiv:2110.05401 [math.NT], 2021.

%t s = {2}; step[s_] := Module[{p = NextPrime[s[[-1]]], r = Times @@ s}, While[! Divisible[r, (p + 1)/2] || ! Divisible[r, Times @@ FactorInteger[(p - 1)/2][[;; , 1]]], p = NextPrime[p]]; Join[s, {p}]]; Nest[step, s, 12] (* _Amiram Eldar_, Nov 30 2022 *)

%Y Similar to A001259.

%Y See also A358718 and A358719.

%K nonn,full,fini

%O 1,1

%A _Lorenzo Sillari_, Nov 28 2022

%E Keywords 'full' and 'fini' added by _Max Alekseyev_, Feb 19 2024

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Last modified April 28 04:16 EDT 2024. Contains 372020 sequences. (Running on oeis4.)