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A358535
a(1) = 1; let S(n) = Sum_{j=1..n-1} a(j) and let T(n) = Sum_{j=1..n-1} d(a(j)) where d(n) = A000005(n). a(n) = least novel k such that (T(n)+d(k)) | (S(n)+k).
1
1, 2, 7, 8, 12, 27, 9, 18, 24, 64, 36, 152, 72, 128, 56, 84, 148, 80, 96, 316, 178, 88, 132, 206, 214, 104, 156, 622, 288, 344, 136, 204, 529, 228, 586, 343, 396, 484, 184, 276, 498, 384, 530, 225, 450, 469, 468, 549, 449, 511, 232, 348, 479, 545, 248, 372, 509
OFFSET
1,2
COMMENTS
In other words, for n > 1, a(n) = smallest k not in a(1)..a(n-1) such that the partial sums of the number of divisors of a(j) divides the partial sum of a(j), 1 <= j < n.
Conjecture: 3 does not appear in the sequence.
LINKS
Michael De Vlieger, Log log scatterplot of a(n), n = 1..40000.
Michael De Vlieger, Annotated log log scatterplot of a(n), n = 1..5000, color coded to show primes in red, composite prime powers in gold, squarefree composites in green, products of composite prime powers in large light blue, and other numbers in dark blue.
EXAMPLE
a(2) = 2 since t(1) + d(2) | s(1) + 2 = 1+2 | 1+2 = 3 | 3,
a(3) = 7 since t(2) + d(7) | s(2) + 7 = 3+2 | 3+7 = 5 | 10,
a(4) = 8 since t(3) + d(8) | s(3) + 8 = 5+4 | 10+8 = 9 | 18,
a(5) = 12 since t(4) + d(12) | s(4) + 12 = 9+6 | 18+12 = 15 | 30,
a(6) = 27 since t(5) + d(27) | s(5) + 27 = 15+4 | 30+27 = 19 | 57, etc.
MATHEMATICA
nn = 2^10; c[_] = False; a[1] = s = t = 1; c[1] = True; u = 2; Do[k = u; While[Nand[! c[k], Divisible[(s + k), (t + Set[d, DivisorSigma[0, k]])]], k++]; Set[{a[n], c[k]}, {k, True}]; s += k; t += d; If[k == u, While[c[u], u++]], {n, 2, nn}]; Array[a, nn]
CROSSREFS
Cf. A000005.
Sequence in context: A070044 A129850 A037073 * A329407 A329408 A047239
KEYWORD
nonn
AUTHOR
STATUS
approved