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A357743
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Square array A(n, k), n, k >= 0, read by antidiagonals: A(0, 0) = 0, A(0, 1) = A(1, 0) = 1, for n, k >= 0, A(2*n, 2*k) = A(n, k), A(2*n, 2*k+1) = A(n, k) + A(n, k+1), A(2*n+1, 2*k) = A(n, k) + A(n+1, k), A(2*n+1, 2*k+1) = A(n, k+1) + A(n+1, k).
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2
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0, 1, 1, 1, 2, 1, 2, 3, 3, 2, 1, 3, 2, 3, 1, 3, 4, 5, 5, 4, 3, 2, 5, 3, 6, 3, 5, 2, 3, 5, 6, 5, 5, 6, 5, 3, 1, 4, 3, 5, 2, 5, 3, 4, 1, 4, 5, 7, 8, 7, 7, 8, 7, 5, 4, 3, 7, 4, 9, 5, 10, 5, 9, 4, 7, 3, 5, 8, 9, 7, 8, 11, 11, 8, 7, 9, 8, 5, 2, 7, 5, 8, 3, 9, 6, 9, 3, 8, 5, 7, 2
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OFFSET
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0,5
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COMMENTS
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This sequence is closely related to A002487 and A355855: we can build this sequence:
- by starting from an equilateral triangle with values 0, 1, 1:
0
/ \
1---1
- and repeatedly applying the following substitution:
t
/ \
t / \
/ \ --> t+u---t+v
u---v / \ / \
/ \ / \
u----u+v----v
The sequence reduced modulo an odd prime number presents rich nonperiodic patterns (see illustrations in Links section).
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LINKS
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FORMULA
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A(n, k) = A(k, n).
A(n, 1) = A007306(n+1) for any n > 0.
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EXAMPLE
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Array A(n, k) begins:
n\k | 0 1 2 3 4 5 6 7 8 9 10
----+---------------------------------------
0 | 0 1 1 2 1 3 2 3 1 4 3
1 | 1 2 3 3 4 5 5 4 5 7 8
2 | 1 3 2 5 3 6 3 7 4 9 5
3 | 2 3 5 6 5 5 8 9 7 8 11
4 | 1 4 3 5 2 7 5 8 3 9 6
5 | 3 5 6 5 7 10 11 9 8 11 11
6 | 2 5 3 8 5 11 6 11 5 10 5
7 | 3 4 7 9 8 9 11 10 7 7 12
8 | 1 5 4 7 3 8 5 7 2 9 7
9 | 4 7 9 8 9 11 10 7 9 14 17
10 | 3 8 5 11 6 11 5 12 7 17 10
.
The first antidiagonals are:
0
1 1
1 2 1
2 3 3 2
1 3 2 3 1
3 4 5 5 4 3
2 5 3 6 3 5 2
3 5 6 5 5 6 5 3
1 4 3 5 2 5 3 4 1
4 5 7 8 7 7 8 7 5 4
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PROG
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(PARI) A(n, k) = { if (n==0 && k==0, 0, n==1 && k==0, 1, n==0 && k==1, 1, n%2==0 && k%2==0, A(n/2, k/2), n%2==0, A(n/2, (k-1)/2) + A(n/2, (k+1)/2), k%2==0, A((n-1)/2, k/2) + A((n+1)/2, k/2), A((n+1)/2, (k-1)/2) + A((n-1)/2, (k+1)/2)); }
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CROSSREFS
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See A358871 for a similar sequence.
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KEYWORD
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AUTHOR
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STATUS
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approved
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