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a(n) = Sum_{k=0..n} k^binomial(n,k).
0

%I #6 Aug 24 2022 12:09:55

%S 0,1,3,12,150,61103,4560574625,1180642129099670883352,

%T 1395184353688945915375285901200638422723404,

%U 11754943508230112085264929216560108802852371298464244215700837207032911162905441549473573

%N a(n) = Sum_{k=0..n} k^binomial(n,k).

%o (PARI) a(n) = sum(k=0, n, k^binomial(n, k));

%Y Cf. A001315, A064405, A087314.

%K nonn,easy

%O 0,3

%A _Seiichi Manyama_, Aug 24 2022