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A353732
Inverse permutation to A352808: a(n) = index where n appears in A352808.
3
0, 1, 2, 6, 3, 4, 10, 11, 5, 7, 8, 18, 12, 19, 32, 44, 9, 16, 14, 24, 13, 17, 15, 45, 20, 21, 50, 56, 51, 52, 62, 63, 22, 25, 26, 27, 28, 29, 33, 40, 23, 30, 34, 78, 48, 70, 79, 122, 36, 64, 38, 84, 37, 71, 82, 98, 83, 85, 94, 123, 92, 148, 134, 210, 31, 41, 35, 46, 42, 47, 43, 72, 49, 53, 57, 73, 54, 76, 128, 162, 39, 65, 58, 96, 55, 68, 60
OFFSET
0,3
LINKS
PROG
(Python)
from itertools import count, islice
def agen(): # generator of terms
A352808lst = [0, 1]; A352808set = {0, 1}; yield from [0, 1]
mink = 2
for n in count(2):
ahalf, k = A352808lst[n//2], mink
while k in A352808set or k&ahalf: k += 1
A352808lst.append(k); A352808set.add(k)
while mink in A352808set: yield A352808lst.index(mink); mink += 1
print(list(islice(agen(), 87))) # Michael S. Branicky, May 17 2022
CROSSREFS
Sequence in context: A130108 A201746 A362552 * A026203 A317025 A354804
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, May 17 2022
STATUS
approved