login
Indices k where A225401(k) = 0.
1

%I #11 Apr 16 2022 09:40:25

%S 3,23,26,32,42,46,48,51,54,84,100,101,119,123,136,184,185,202,206,216,

%T 241,263,265,272,273,284,293,323,325,332,351,352,362,392,400,406,408,

%U 410,425,432,447,449,450,466,484,488,490,497,498,509,512,522,532,534,573,585,593,595

%N Indices k where A225401(k) = 0.

%C These are also the indices k such that A352992(k+1) < A352992(k).

%e 3 is a term because A225401(3) = 0; and we have A352992(4)=753 < A352992(3)=1753.

%o (PARI) lista(nn) = {my(n=0, list = List()); for(i=1, nn, m=7*(10^i-1)/9; for(x=0, 9, if(((n+(x*10^(i-1)))^3)%(10^i)==m, n=n+(x*10^(i-1)); if (x==0, listput(list, i-1)); break;););); Vec(list);} \\ after A225401

%Y Cf. A225401, A352992.

%K nonn,base

%O 1,1

%A _Michel Marcus_, Apr 15 2022