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Maximal permanent of an n X n symmetric matrix using the integers 1 to n*(n + 1)/2.
2

%I #6 Feb 15 2022 16:05:46

%S 1,1,11,420,41451,7985639,2779152652

%N Maximal permanent of an n X n symmetric matrix using the integers 1 to n*(n + 1)/2.

%e a(3) = 420:

%e 1 5 6

%e 5 3 4

%e 6 4 2

%e a(4) = 41451:

%e 1 5 8 10

%e 5 4 9 7

%e 8 9 3 6

%e 10 7 6 2

%Y Cf. A000217, A351153, A351610 (minimal).

%Y Cf. A350566, A350859, A350938, A350940, A351020, A351022.

%K nonn,hard,more

%O 0,3

%A _Stefano Spezia_, Feb 14 2022

%E a(5)-a(6) from _Hugo Pfoertner_, Feb 15 2022