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a(n) = Sum_{k=0..n} k! * 3^k * k^n * Stirling1(n,k).
3

%I #18 Feb 04 2022 08:22:49

%S 1,3,69,3948,422082,72567522,18304992558,6367730357160,

%T 2921446409138136,1709074810258369776,1241694104839498851552,

%U 1096850187800368469477424,1157691464039682741551221152,1438880771284303822650674399664

%N a(n) = Sum_{k=0..n} k! * 3^k * k^n * Stirling1(n,k).

%H Seiichi Manyama, <a href="/A350720/b350720.txt">Table of n, a(n) for n = 0..213</a>

%F E.g.f.: Sum_{k>=0} (3 * log(1 + k*x))^k.

%t a[0] = 1; a[n_] := Sum[k! * 3^k * k^n * StirlingS1[n, k], {k, 1, n}]; Array[a, 14, 0] (* _Amiram Eldar_, Feb 03 2022 *)

%o (PARI) a(n) = sum(k=0, n, k!*3^k*k^n*stirling(n, k, 1));

%o (PARI) my(N=20, x='x+O('x^N)); Vec(serlaplace(sum(k=0, N, (3*log(1+k*x))^k)))

%Y Cf. A320083, A350719.

%Y Cf. A195263, A335531, A350721.

%K nonn

%O 0,2

%A _Seiichi Manyama_, Feb 03 2022