OFFSET
3,1
COMMENTS
T(n,b) must be nonzero for all b >= 2, and so this triangle is actually the upper left corner of an array with infinitely long rows (it is believed that there are also infinitely many rows).
Since T(n,b) = m/2 for all b > m/2, we may truncate row n after m/2 terms. The rows do not change beyond that point.
EXAMPLE
Triangle begins as follows:
n m Row n
3 10 [7, 7, 8, 7, 5],
4 14 [11, 11, 10, 9, 12, 10, 7],
5 22 [19, 17, 20, 17, 16, 17, 18, 15, 20, 16, 11],
6 38 [35, 34, 31, 33, 29, 31, 33, 31, 28, 29, 30, 25, 32, 26, 34, 27, 36, 28, 19],
7 62 [58, 58, 55, 57, 56, 55, 52, 51, 49, 51, 53, 49, 57, 52, 46, 47, 48, 49, 50, 41, 52, 42, 54, 43, 56, 44, 58, 45, 60, 46, 31],
8 94 [90, 89, 89, 87, 87, 83, 89, 79, 83, 82, 80, 77, 86, 82, 77, 79, 81, 74, 85, 77, 89, 80, 70, 71, 72, 73, 74, 75, 76, 77, 78, 63, 80, 64, 82, 65, 84, 66, 86, 67, 88, 68, 90, 69, 92, 70, 47],
...
For n = 3, m = A230624(3) = 10, and row 3 of the triangle is [7, 7, 8, 7, 5], corresponding to the identities (where x_b is the base-b expansion of x):
10 = 111_2 + 3 = 7 + 3,
= 21_3 + 3 = 7 + 3
= 20_4 + 2 = 8 + 2
= 12_5 + 3 = 7 + 3
= 5_b + 5 = 5 + 5 for all b >= 6.
CROSSREFS
KEYWORD
nonn,tabf,base
AUTHOR
N. J. A. Sloane, Dec 30 2021
STATUS
approved