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A349294
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Numbers m such that there exists a permutation p of {1,2,...,m} with p(k) dividing p(k+1) + p(k+2) for all k in {1,2,...,m-2}.
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1
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 34, 37, 38, 51
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OFFSET
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1,2
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COMMENTS
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Numbers m such that A349288(m) > 0.
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LINKS
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EXAMPLE
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m=9 belongs to this sequence since the permutation p = (1, 3, 8, 7, 9, 5, 4, 6, 2) satisfies the condition.
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CROSSREFS
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KEYWORD
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nonn,hard,more
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AUTHOR
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STATUS
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approved
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