

A349294


Numbers m such that there exists a permutation p of {1,2,...,m} with p(k) dividing p(k+1) + p(k+2) for all k in {1,2,...,m2}.


1



1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 34, 37, 38, 51
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OFFSET

1,2


COMMENTS

Numbers m such that A349288(m) > 0.


LINKS



EXAMPLE

m=9 belongs to this sequence since the permutation p = (1, 3, 8, 7, 9, 5, 4, 6, 2) satisfies the condition.


CROSSREFS



KEYWORD

nonn,hard,more


AUTHOR



STATUS

approved



