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a(n) = Sum_{k=1..n} n^Omega(k).
2

%I #11 Sep 09 2021 10:46:14

%S 1,3,7,25,41,91,127,673,1009,1441,1871,4093,5149,6553,8191,75361,

%T 95201,124543,153217,194561,234781,280897,332949,723673,849601,991251,

%U 1168831,1369117,1569597,1818301,2065531,35891553,41771137,48397471,55839561,65848861,75339253

%N a(n) = Sum_{k=1..n} n^Omega(k).

%H Michael De Vlieger, <a href="/A347614/b347614.txt">Table of n, a(n) for n = 1..1000</a>

%e a(5) = Sum_{k=1..5} 5^Omega(k) = 5^0 + 5^1 + 5^1 + 5^2 + 5^1 = 41.

%t Table[Sum[n^PrimeOmega[k], {k, n}], {n, 40}]

%o (PARI) a(n) = sum(k=1, n, n^bigomega(k)); \\ _Michel Marcus_, Sep 09 2021

%Y Cf. A001222 (Omega), A347616.

%K nonn

%O 1,2

%A _Wesley Ivan Hurt_, Sep 08 2021