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Number of partitions of n^n into exactly n parts.
2

%I #14 Sep 08 2021 22:28:16

%S 0,1,2,61,117874,33219689231,2559960025059106420,

%T 85975912953927216830024650654,

%U 1841153609473379088124269084031755459049386

%N Number of partitions of n^n into exactly n parts.

%F a(n) = [x^(n^n-n)] Product_{k=1..n} 1/(1-x^k).

%o (PARI) a(n) = polcoef(prod(k=1, n, 1/(1-x^k+x*O(x^(n^n-n)))), n^n-n);

%Y Cf. A206240, A304176, A347605, A347607.

%K nonn,more

%O 0,3

%A _Seiichi Manyama_, Sep 08 2021