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%I #15 Oct 28 2021 06:31:36
%S 2,5,4,7,10,8,10,14,18,14,13,20,26,31,25,15,26,36,46,53,42,18,30,47,
%T 63,79,88,71,20,36,55,81,107,132,146,117,23,40,65,96,136,178,219,239,
%U 193,26,46,73,112,162,225,294,359,391,315,28,52,84,127,189,269
%N Rectangular array (T(n,k)), by downward antidiagonals: T(n,k) = position of k in the ordering of {h*r^m, r = 1/(golden ratio), h >= 1, 0 <= m <= n}.
%C Row 1: A001950 (upper Wythoff sequence);
%C row 2: A283234;
%C row 3: A190508;
%C col 1: A020956.
%e Corner:
%e 2, 5, 7, 10, 13, 15, 18, 20, 23, ...
%e 4, 10, 14, 20, 26, 30, 36, 40, 46, ...
%e 8, 18, 26, 36, 47, 55, 65, 73, 84, ...
%e 14, 31, 46, 63, 81, 96, 112, 127, 145, ...
%e 25, 53, 79, 107, 136, 162, 189, 215, 244, ...
%e 42, 88, 132, 178, 225, 269, 314, 358, 405, ...
%e 71, 146, 219, 294, 370, 443, 517, 590, 666, ...
%e ...
%t z = 1000; r = N[(-1+Sqrt[5])/2];
%t s[m_] := Range[z] r^m; t[0] = s[0];
%t t[n_] := Sort[Union[s[n], t[n - 1]]]
%t row[n_] := Flatten[Table[Position[t[n], N[k]], {k, 1, z}]]
%t TableForm[Table[row[n], {n, 1, 10}]] (* A347068, array *)
%t w[n_, k_] := row[n][[k]];
%t Table[w[n - k + 1, k], {n, 12}, {k, n, 1, -1}] // Flatten (* A347068, sequence *)
%Y Cf. A001950, A020956, A283234, A190508, A347065, A347066, A347067, A347069.
%K nonn,tabl
%O 1,1
%A _Clark Kimberling_, Sep 02 2021