|
|
A344136
|
|
Number of linear intervals in the Tamari lattices.
|
|
7
|
|
|
1, 3, 12, 49, 198, 792, 3146, 12441, 49062, 193154, 759696, 2986458, 11737820, 46134090, 181350630, 713046345, 2804421510, 11033453970, 43424181240, 170965500030, 673354218420, 2652994345560, 10456457024052, 41227321016394
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,2
|
|
COMMENTS
|
The description is conjectural. An interval is linear if it is isomorphic to a total order. The conjecture has been checked up to the term 49062 for n=9.
Apparently odd exactly when n is a power of 2.
|
|
LINKS
|
|
|
FORMULA
|
a(n) = (3/2)*binomial(2*n, n)*(n^2 - n + 2)/(n + 2)/(n + 1).
a(n) = binomial(2*n, n)/(n + 1) + binomial(2*n-1, n-2) + 2*binomial(2*n-1, n-3).
a(n) ~ (3/2) * 4^n * (1 - 33/(8*n)) / sqrt(n*Pi). - Peter Luschny, May 10 2021
a(n) = a(n-1)*2*(2*n - 1)*(n^2 - n + 2)/((n + 2)*(n^2 - 3*n + 4)) for n > 1. - Chai Wah Wu, May 13 2021
|
|
EXAMPLE
|
All 3 intervals in the lattice of cardinality 2 are linear. Among 13 intervals in the pentagon, only one is not linear.
|
|
MATHEMATICA
|
Array[(3/2) Binomial[2 #, #]*(#^2 - # + 2)/(# + 2)/(# + 1) &, 24] (* Michael De Vlieger, Sep 09 2022 *)
|
|
PROG
|
(Sage)
[3/2*binomial(2*n, n)*(n**2-n+2)/(n+2)/(n+1) for n in range(1, 30)]
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|