%I #6 May 09 2021 15:34:03
%S 2,11,23,53,12451,36779999
%N a(n) is the least prime that begins a sequence of at least n distinct primes under iteration of A061762.
%e 12451 is prime and A061762(12451) = 1*2*4*5*1+1+2+4+5+1 = 53.
%e 53 is prime and A061762(53) = 5*3+5+3 = 23.
%e 23 is prime and A061762(23) = 2*3+2+3 = 11.
%e 11 is prime and A061762(11) = 1*1+1+1 = 3.
%e 3 is prime and A061762(3) = 3+3 = 6 is not prime.
%e Thus 12451 begins a sequence of 5 distinct primes under the iteration of A061762. Since 12451 is the least such prime, a(5) = 12451.
%p f:= proc(n) local L;
%p L:= convert(n,base,10);
%p convert(L,`+`)+convert(L,`*`)
%p end proc:
%p g:= proc(n) local S,v;
%p S:= {n}:
%p v:= n;
%p do
%p v:= f(v);
%p if member(v,S) or not isprime(v) then return nops(S) fi;
%p S:= S union {v}
%p od
%p end proc:
%p R:= NULL: p:= 1: m:= 0:
%p while m < 5 do
%p p:= nextprime(p);
%p v:= g(p);
%p if v > m then R:= R, p$(v-m); m:= v fi
%p od:
%p R;
%Y Cf. A061762, A214629.
%K nonn,base,more
%O 1,1
%A _J. M. Bergot_ and _Robert Israel_, May 07 2021