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%I #30 Jun 11 2021 05:05:56
%S 1,2,31,179,787,6631,2456299,33235913,158433901,17980176031,
%T 2794938616471,8546650588601,5595650767265101,35480190026972501,
%U 15523069639558351459,455264603021602214213,57023540590242398853649,949437664962426221725789,5469912218467062529961407
%N a(n) = numerator of (1/e) * Sum_{a_1>=1, a_2>=1, ... , a_n>=1} a_1 * a_2 * ... * a_n / (a_1 + a_2 + ... + a_n)!.
%D O. Furdui, Limits, Series and Fractional Part Integrals. Problems in Mathematical Analysis, Springer, New York, 2013. See Problem 3.114 and 3.118.
%H Seiichi Manyama, <a href="/A343830/b343830.txt">Table of n, a(n) for n = 1..367</a>
%H Math StackExchange, <a href="https://math.stackexchange.com/questions/2344699/compute-s-n-sum-limits-a-1-a-2-cdots-a-n-1-infty-fraca-1a-2-cdots-a-n?rq=1">Compute S_n = Sum_{a_1 a_2 ... a_n >=1} a_1 a_2 ... a_n/(a_1+a_2+...+a_n)!</a>
%F b(n) = (1/e) * Sum_{a_1>=1, a_2>=1, ... , a_n>=1} a_1 * a_2 * ... * a_n / (a_1 + a_2 + ... + a_n)! = Sum_{j=0..n} (-1)^(n+j-1) * binomial(n,j) * Sum_{k=0..n+j-1} (-1)^k/k! = Sum_{k=0..n-1} binomial(n-1,k)/(k+n)!.
%F a(n) = numerator of b(n).
%e 1, 2/3, 31/120, 179/2520, 787/51840, 6631/2494800, 2456299/6227020800, ...
%t a[n_] := Numerator @ Sum[Binomial[n - 1, k]/(k + n)!, {k, 0, n - 1}]; Array[a, 20] (* _Amiram Eldar_, May 01 2021 *)
%o (PARI) a(n) = numerator(sum(j=0, n, (-1)^(n+j-1)*binomial(n, j)*sum(k=0, n+j-1, (-1)^k/k!)));
%o (PARI) a(n) = numerator(sum(k=0, n-1, binomial(n-1, k)/(k+n)!));
%Y Cf. A343831 (denominator), A343832.
%K nonn,frac
%O 1,2
%A _Seiichi Manyama_, Apr 30 2021
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