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Total number of partitions of k*n into 3 parts for k = 1..n.
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%I #7 Apr 05 2021 20:39:41

%S 0,1,11,39,114,273,571,1086,1925,3206,5101,7800,11533,16575,23252,

%T 31911,42987,56943,74304,95662,121682,153060,190614,235200,287758,

%U 349317,421001,503975,599560,709125,834145,976206,1137011,1318314,1522059,1750248,2005011,2288611

%N Total number of partitions of k*n into 3 parts for k = 1..n.

%H <a href="/index/Par#part">Index entries for sequences related to partitions</a>

%F a(n) = Sum_{k=1..n} Sum_{j=1..floor(k*n/3)} Sum_{i=j..floor((k*n-j)/2)} 1.

%t Table[Sum[Sum[Sum[1, {i, j, Floor[(k*n - j)/2]}], {j, Floor[k*n/3]}], {k, n}], {n, 50}]

%Y Cf. A069905.

%K nonn

%O 1,3

%A _Wesley Ivan Hurt_, Apr 05 2021