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Fourier coefficients of the modular form (1/t_{6a}^3) * (1-12*sqrt(-3) / t_{6a})^(1/6) * F_{6a}^10.
0

%I #14 Jul 31 2023 07:23:36

%S 0,1,-3,-27,147,-183,-54,-423,1434,1323,-4141,-2580,-972,20394,-1929,

%T -20169,-15597,-7746,58212,-27964,76398,-19683,-117585,-94050,-60696,

%U 474840,-103989,-89910,-72487,148359,100440,-1107363,43554,629289,1257516,517584,-745848,-1430837,-748068

%N Fourier coefficients of the modular form (1/t_{6a}^3) * (1-12*sqrt(-3) / t_{6a})^(1/6) * F_{6a}^10.

%C Here, F_{6a} is the hypergeometric function F(1/3, 1/2; 1; 12*sqrt(-3)/t_{6a}). The definition given on page 23 in the linked manuscript has a minor typo where "t_{3A}" should be "t_{6a}". - _Robin Visser_, Jul 31 2023

%H Masao Koike, <a href="/A004016/a004016.pdf">Modular forms on non-compact arithmetic triangle groups</a>, Unpublished manuscript [Extensively annotated with OEIS A-numbers by N. J. A. Sloane, Feb 14 2021. Sloane wrote 2005 on the first page but the internal evidence suggests 1997.] See page 30.

%o (Sage)

%o def a(n):

%o if n==0: return 0

%o theta2 = sum([1]+[2*x^(k^2/2) for k in range(1, n+1)])

%o theta3 = sum([2*x^((k^2 + k + 1/4)/2) for k in range(n)])

%o phi0 = theta2(x=x^2)*theta2(x=x^6) + theta3(x=x^2)*theta3(x=x^6)

%o phi1 = theta2(x=x^2)*theta3(x=x^6) + theta3(x=x^2)*theta2(x=x^6)

%o phi02, phi12 = phi0(x=x^2), phi1(x=x^2)

%o f = phi0*(phi12^3*(phi02^2 - phi12^2)^3)/8

%o return f.taylor(x, 0, n+1).coefficient(x^(n+1/2)) # _Robin Visser_, Jul 31 2023

%K sign

%O 0,3

%A _Robert C. Lyons_, Feb 15 2021

%E More terms from _Robin Visser_, Jul 31 2023