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%I #20 Jul 01 2023 09:29:00
%S 1,2,0,0,2,3,0,0,0,3,0,0,0,3,4,0,0,0,0,4,0,0,0,0,4,0,0,0,0,4,5,0,0,0,
%T 0,0,5,0,0,0,0,0,5,0,0,0,0,0,5,0,0,0,0,0,5,6,0,0,0,0,0,0,6,0,0,0,0,0,
%U 0,6,0,0,0,0,0,0,6,0,0,0,0,0,0,6,0,0,0,0,0,0,6,7,0
%N The entries in the rows of the n X n identity matrix, multiplied by the size of the matrix (n).
%e For every identity matrix of size n starting with n=1, append n*(each entry of each row of the matrix), e.g., n=1 -> 1, n=2 -> 2,0,0,2, so the first 5 terms of the sequence are 1,2,0,0,2.
%o (Python)
%o import numpy as np
%o def n_id_sequence(iterations):
%o sequence = []
%o for i in range(1,iterations+1):
%o matrix = i*(np.identity(i))
%o for row in matrix:
%o for entry in row:
%o sequence.append(int(entry))
%o return sequence
%Y Cf. A191747 (with 1's), A191748 (locations of nonzero terms), A056520 (start location of each matrix).
%K nonn,easy
%O 1,2
%A _Julia Zimmerman_, Nov 10 2020
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