%I #15 Sep 08 2020 03:29:23
%S 1,1,2,3,3,4,1,3,1,1,7,6,1,12,1,10,1,12,1,3,1,1,21,12,1,6,21,1,1,15,1,
%T 20,1,31,15,1,1,32,13,1,1,18,1,7,25,1,17,38,1,1,1,1,1,26,1,6,1,1,29,
%U 47,1,42,1,1,1,1,61,26,1,25,1,21,1,64,21,1,1,29,1,18
%N a(1) = 1; a(n) = 1 + Product_{k=1..n-1} a(k) (mod n-1).
%C Note that the running product for each a(n) is incrementally computed mod n-1.
%t a[1] = 1; a[n_] := a[n] = 1 + Mod[Product[a[k], {k, 1, n - 1}], n - 1]; Array[a, 100] (* _Amiram Eldar_, Aug 22 2020 *)
%o (Python)
%o def f(n):
%o if n == 1: return 1
%o a = 1
%o for k in range(1, n):
%o a = a * f(k) % (n - 1)
%o return a + 1
%o (PARI) lista(nn) = {my(va = vector(nn)); va[1] = 1; for (n=2, nn, va[n] = 1 + prod(k=1, n-1, va[k]) % (n-1);); va;} \\ _Michel Marcus_, Aug 23 2020
%Y Inspired by A066910.
%Y Cf. A129871 (without the mod operation).
%K nonn
%O 1,3
%A _Matt Donahoe_, Aug 22 2020