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a(n) = (n!)^n * [x^n] 1 / (Sum_{k>=0} (-x)^k / (k!)^n)^n.
0

%I #5 Jul 30 2020 22:49:46

%S 1,1,10,1839,10386076,2920439606255,61647526987008365796,

%T 138198647831589723000626151799,

%U 44295532378421071881332203441924537230328,2630596041328098180368767727753901255310559993154210399,36407288356000016897632843477214290941136877077516693440464220432175060

%N a(n) = (n!)^n * [x^n] 1 / (Sum_{k>=0} (-x)^k / (k!)^n)^n.

%t Table[(n!)^n SeriesCoefficient[1/Sum[(-x)^k/(k!)^n, {k, 0, n}]^n, {x, 0, n}], {n, 0, 10}]

%Y Cf. A212806, A245398, A336665.

%K nonn

%O 0,3

%A _Ilya Gutkovskiy_, Jul 29 2020

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